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A pendulum with a length of 2 m has a period of 2.8 s. What is the period of a pendulum with a length of 8 m

Answer :

Answer:

P = 2 pi (L / g)^1/2

P2 / P1 = (8 / 2)^1/2 = 2

The period would be twice as long or 5.6 sec.

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